2x^2-56x-36=0

Solution for 2x^2-56x-36=0 equation:

2x^2-56x-36=0

a = 2; b = -56; c = -36;
Δ = b2-4ac
Δ = -562-4·2·(-36)
Δ = 3424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3424}=\sqrt{16*214}=\sqrt{16}*\sqrt{214}=4\sqrt{214}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-4\sqrt{214}}{2*2}=\frac{56-4\sqrt{214}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+4\sqrt{214}}{2*2}=\frac{56+4\sqrt{214}}{4}
$